120=10x-4.9x^2

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Solution for 120=10x-4.9x^2 equation: 



120=10x-4.9x^2

We move all terms to the left:

120-(10x-4.9x^2)=0

We get rid of parentheses

4.9x^2-10x+120=0

a = 4.9; b = -10; c = +120;
Δ = b2-4ac
Δ = -102-4·4.9·120
Δ = -2252
Delta is less than zero, so there is no solution for the equation

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